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Electromagnetic Waves (EM Waves)

Electromagnetic waves are waves that can travel through the vacuum of space as well as through various mediums. They are formed when an electric field and a magnetic field interact and oscillate together at right angles to each other. These waves transport energy through space.

Characteristics of Electromagnetic Waves:

  1. Transverse Nature:

    • Electromagnetic waves are transverse waves, meaning the oscillations of the electric and magnetic fields are perpendicular to the direction of wave propagation.
  2. Speed of Light:

    • In a vacuum, the speed of an electromagnetic wave is approximately 3 x 10^8 meters per second (the speed of light, c).
  3. Wavelength and Frequency:

    • The wavelength (λ\lambda) is the distance between two consecutive crests or troughs of a wave.
    • The frequency (f) is the number of complete wave cycles that pass a point per second.
    • The relationship between wavelength, frequency, and the speed of light is given by: c=λfc = \lambda \cdot fwhere:
      • cc is the speed of light,
      • λ\lambda is the wavelength,
      • ff is the frequency.
  4. Energy:

    • The energy of an electromagnetic wave is directly proportional to its frequency: E=hfE = h \cdot fwhere:
      • EE is energy,
      • hh is Planck’s constant (6.626×1034Js6.626 \times 10^{-34} J \cdot s),
      • ff is the frequency of the wave.

The Electromagnetic Spectrum:

Electromagnetic waves vary in wavelength and frequency. This range is known as the electromagnetic spectrum, which includes different types of waves with distinct properties.

  1. Radio Waves:

    • Wavelength: >102m> 10^2 \, m
    • Frequency: <109Hz< 10^9 \, Hz
    • Uses: Communication, broadcasting, and radar.
  2. Microwaves:

    • Wavelength: 102m10^{-2} \, m to 103m10^{-3} \, m
    • Frequency: 109Hz10^9 \, Hz to 1012Hz10^{12} \, Hz
    • Uses: Cooking (microwave ovens), satellite communication, and radar.
  3. Infrared (IR):

    • Wavelength: 105m10^{-5} \, m to 106m10^{-6} \, m
    • Frequency: 1012Hz10^{12} \, Hz to 1014Hz10^{14} \, Hz
    • Uses: Thermal imaging, remote controls, and heat sensing.
  4. Visible Light:

    • Wavelength: 4×107m4 \times 10^{-7} \, m to 7×107m7 \times 10^{-7} \, m
    • Frequency: 4×1014Hz4 \times 10^{14} \, Hz to 7×1014Hz7 \times 10^{14} \, Hz
    • Uses: Human vision.
  5. Ultraviolet (UV):

    • Wavelength: 108m to 109m10^{-9} \, m
    • Frequency: 1015Hz10^{15} \, Hz to 1016Hz10^{16} \, Hz
    • Uses: Sterilization, blacklights, and skin tanning.
  6. X-rays:

    • Wavelength: 1011m10^{-11} \, m to 108m10^{-8} \, m
    • Frequency: 1016Hz10^{16} \, Hz to 1020Hz
    • Uses: Medical imaging and cancer treatment.
  7. Gamma Rays:

    • Wavelength: <1012m< 10^{-12} \, m
    • Frequency: >1020Hz> 10^{20} \, Hz
    • Uses: Cancer treatment and sterilization.

Properties of Electromagnetic Waves:

  1. Reflection:

    • EM waves can reflect off surfaces, obeying the laws of reflection (angle of incidence = angle of reflection).
  2. Refraction:

    • When electromagnetic waves pass from one medium to another, they change speed and direction. This is known as refraction.
  3. Diffraction:

    • EM waves can bend around obstacles and spread out through small openings, a phenomenon known as diffraction.
  4. Interference:

    • When two or more electromagnetic waves meet, they can interfere with each other, leading to constructive or destructive interference.

Speed of EM Waves in Different Mediums:

  1. In a Vacuum:

    • As mentioned, the speed of light (EM waves) in a vacuum is c=3.00×108m/sc = 3.00 \times 10^8 \, \text{m/s}.
  2. In Other Media:

    • When electromagnetic waves travel through other materials (like air, water, glass, etc.), their speed decreases due to the refractive index of the medium.
    • The refractive index (n) of a medium is given by: n=cvn = \frac{c}{v} where:
      • cc is the speed of light in a vacuum,
      • vv is the speed of light in the medium.

    The speed of an EM wave in a medium can be calculated as:

    v=cnv = \frac{c}{n}

    For example:

    • In air, the refractive index is close to 1, so the speed of EM waves is nearly the same as in a vacuum.
    • In water, the refractive index is around 1.33, so the speed of EM waves in water would be slower: v=3.00×1081.332.26×108m/sv = \frac{3.00 \times 10^8}{1.33} \approx 2.26 \times 10^8 \, \text{m/s}
  3. In Materials like Glass or Diamond:

    • In glass, the refractive index typically ranges from 1.5 to 1.6, so the speed of light would be slower than in air.
    • In diamond, the refractive index is about 2.42, leading to even slower speeds.

Solved Problems

1. The speed of light in water is approximately 2.25×108m/s2.25 \times 10^8 \, \text{m/s}. Calculate the refractive index of water.

Solution:
We know the relationship between the speed of light in a vacuum (cc) and the speed of light in a medium (vv):

n=cvn = \frac{c}{v}

Where:

  • c=3.00×108m/s (speed of light in vacuum),
  • v=2.25×108m/sv = 2.25 \times 10^8 \, \text{m/s} (speed of light in water).

Now, substituting the values into the equation:

n=3.00×1082.25×108n = \frac{3.00 \times 10^8}{2.25 \times 10^8} n=1.33

The refractive index of water is n=1.33n = 1.33.

2. A radio wave has a frequency of 9.0×106Hz9.0 \times 10^6 \, \text{Hz}. What is its wavelength in a vacuum?

Solution:
We can use the relationship between wavelength, frequency, and the speed of light:

c=λf

Where:

  • c=3.00×108m/sc = 3.00 \times 10^8 \, \text{m/s} (speed of light in a vacuum),
  • λ\lambda is the wavelength,
  • f=9.0×106Hzf = 9.0 \times 10^6 \, \text{Hz} (frequency).

Rearrange the formula to solve for wavelength (λ\lambda):

λ=cf​

Now, substitute the values:

λ=3.00×1089.0×106\lambda = \frac{3.00 \times 10^8}{9.0 \times 10^6} λ=33.33m\lambda = 33.33 \, \text{m}

The wavelength of the radio wave is 33.33m33.33 \, \text{m}.

3. The speed of light in glass is 2.0×108m/s2.0 \times 10^8 \, \text{m/s}. If the refractive index of glass is 1.5, calculate the speed of light in a vacuum.

Solution:
We know the formula for the refractive index:

n=cv​

Where:

  • n=1.5n = 1.5 (refractive index of glass),
  • v=2.0×108m/sv = 2.0 \times 10^8 \, \text{m/s} (speed of light in glass),
  • cc is the speed of light in a vacuum.

Rearrange the formula to solve for cc:

c=nv

Now, substitute the values:

c=1.5×2.0×108c = 1.5 \times 2.0 \times 10^8
c=3.0×108m/sc = 3.0 \times 10^8 \, \text{m/s}

The speed of light in a vacuum is 3.0×108m/s3.0 \times 10^8 \, \text{m/s}, which matches the known speed of light.


4. An electromagnetic wave has a frequency of 5.0×1014Hz5.0 \times 10^{14} \, \text{Hz}. What is its energy?

Solution:
The energy of an EM wave can be calculated using the formula:

E=hfE = h \cdot f

Where:

  • EE is the energy of the wave,
  • h=6.626×1034Jsh = 6.626 \times 10^{-34} \, \text{J} \cdot \text{s} (Planck’s constant),
  • f=5.0×1014Hzf = 5.0 \times 10^{14} \, \text{Hz} (frequency).

Now, substitute the values:

E=(6.626×1034)×(5.0×1014)E = (6.626 \times 10^{-34}) \times (5.0 \times 10^{14})
E=3.313×1019J

The energy of the electromagnetic wave is 3.313×1019J3.313 \times 10^{-19} \, \text{J}.

Problems

1. A light wave travels through a material with a refractive index of 1.81.8 and a speed of 2.4×108m/s2.4 \times 10^8 \, \text{m/s}. Calculate the speed of light in a vacuum.

2. A light wave has a wavelength of 600nm600 \, \text{nm} (nanometers) and travels through air. Calculate the frequency of the light wave.

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